What percentage of offsprings in a monohybrid cross will be homozygous dominant?

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In a monohybrid cross, where one trait is being examined and each parent is heterozygous for that trait (for example, assuming a trait governed by a gene with two alleles, one dominant and one recessive), the offspring can have different combinations of these alleles.

Each parent can contribute either a dominant allele or a recessive allele. If we denote the dominant allele as 'A' and the recessive allele as 'a', a cross between two heterozygous parents (Aa x Aa) will yield the following combinations for the offspring:

  1. Homozygous dominant (AA)
  2. Heterozygous (Aa)
  3. Homozygous recessive (aa)

When we perform a Punnett square to show these combinations, we will find that:

  • One combination results in homozygous dominant (AA),
  • Two combinations result in heterozygous (Aa),
  • One combination results in homozygous recessive (aa).

The fraction of the offspring that are homozygous dominant (AA) from the total of four combinations is 1 out of 4, which rounds to 25%. Therefore, when asked about the percentage of offspring that will be homozygous dominant from

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